WebAug 3, 2010 · C# DemographicHashIntersectComparer demographicIntersectComparer = new DemographicHashIntersectComparer (); var updatedPatientInfos = newHashValues.Intersect (lastTransmittedHashes, demographicIntersectComparer); LINQ to SQL has an overridden Intersect method which allows us to pass our own custom … WebYou can change fooKeys to HashSet (if it's not one already) to make Contains () method call O (1) instead of O (n): var keesSet = new HashSet (fooKeys); var matchedFoos = foos.Where (f => keesSet.Contains (f.Key)); But with collections that big it will still require a fair amount of time to perform the search. Share
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WebDec 22, 2024 · Intersect or IntersectBy: Returns the set intersection, which means elements that appear in each of two collections. Not applicable. Enumerable.Intersect Enumerable.IntersectBy Queryable.Intersect Queryable.IntersectBy: Union or UnionBy: Returns the set union, which means unique elements that appear in either of two … WebFeb 13, 2024 · performance - C# Fastest way to intersect lists of strings - Stack Overflow C# Fastest way to intersect lists of strings Ask Question Asked 3 years, 1 month ago Modified 3 years, 1 month ago Viewed 879 times 3 I am using hashet, linq Intersect () and Count () to find intersection of two lists of strings. Code being used imgrock mount
performance - Fast intersection of sets: C++ vs C# - Stack Overflow
WebMar 13, 2024 · Also applying larger.Intersect(smaller) rather than the opposite is very important, in my case, it gave 35% improvements. Also ordering the list before applying intersect gave another 7-8%. Another thing to keep in mind that depending on the use … WebFeb 10, 2010 · INTERSECT is meant to find the distinct values combining two queries. That's a very different goal than the INNER JOIN which is not finding distinct values, but … WebFeb 27, 2015 · Instead of using the IEnumerable<>.Intersect method you can do the same thing in a loop, but using the fact that you already have a hash set. Checking if a value exists in a hash set is very fast, so you can just loop through the items in the smallest set and look for matching values in the next set, and put them in a new set. imgrock milass-011