Webclass Solution {public void duplicateZeros (int [] arr) {int movePos = 0; int lastPos = arr. length - 1; // Only check [0, lastPos - movePos] for (int i = 0; i <= lastPos - movePos; i … Web3 mar 2024 · Solution 1 :- Using for loop. class Solution {. public void duplicateZeros (int [] arr) {. for (int i=0; i i; j--) {. …

LeetCode 1089 : Duplicate Zeros EASY JAVA Detailed Solution

Webclass Solution {public void duplicateZeros (int [] arr) {int numOfZeros = 0; for (int num: arr) {numOfZeros += num == 0? 1: 0;} int i = arr. length - 1; int j = arr. length + numOfZeros - … Web26 ott 2015 · This is an O (n) solution to the problem: var moveZeroes = function (nums) { let count = 0; for (let i = 0; i < nums.length; i++) { if (nums [i] !== 0) { nums [count++] = nums [i]; } } for (let i = count; i < nums.length; i++) { nums [i] = 0; } return nums; }; Share Follow edited Jan 14, 2024 at 20:10 ggorlen 41.7k 7 67 92 inspiration for the book ghost

Java Faster than 99.34% Solution - Duplicate Zeros - LeetCode

Web19 apr 2024 · First, think about what the array might look like if we extended it to contain all the elements, including the duplicate zeros. It would be an array of length arr.length + number_of_zeros_in_the_array. If we had an array that could contain the dulicate zeros and the existing elements, it would look like this: The length of the first array is 8. WebSolution: Iterate over the array, whenever if 0 shift from the next element. As you shift, move one step forward when you iterate. Here is my java implementation: Web16 gen 2016 · 1 Answer Sorted by: 9 Simple regexp with replaceAll will do it. String s = "1903895810000"; System.out.println (s.replaceAll ("0+$", "")); : s.replace (0, "") will not work here, because it will remove all zeros from the string, so you can't use it. So, here I used replaceAll, that uses regular expressions to match replacement string. jesus in every book in the bible